| Topic | Hello World | 
|---|---|
| Git sample | HelloWorld.scala & HelloWorldWithoutMain.scala | 
| References | Scala In Depth | 
HelloWorld With main() Method
- Open Scala program HelloWorld.scala
 
object HelloWorld {
  /**
   *  Entry point of program : equivalent of Java main method
   *  Parameter passed : 'scala.Array' of 'Predef.String'
   *  Property 'scala.Predef.String' eventually calls 'java.lang.String'
   *  Scala object 'scala.Predef' is a placeholder for mostly used Scala classes
   */
  def main(args: Array[String]): Unit = {
    /* Control flow : scala.Predef.println --> scala.Console.println --> java.io.PrintStream.println */
    println("Hello World")
  }
}
HelloWorld Without main Method
Scala provides
scala.Appclass to avoidmainmethodOpen Scala program HelloWorldWithoutMain.scala
object HelloWorldWithoutMain extends App {
  /* Control flow : scala.Predef.println --> scala.Console.println --> java.io.PrintStream.println */
  println("Hello World")
}
Input/Output in Scala
To print the value on console you can use print :
print("Hello World")To print the value on console in a new line you can use println
println("Hello World")To print the formatted value use
printf(like C)printf("Hello, %s! You are %d years old.\n", "John", 32)Read a line of input from the console with the
readLinefunction.To read a specific value, use specific methods in Scala class scala.io.StdIn
  scala.io.StdIn.readInt
  scala.io.StdIn.readChar
  scala.io.StdIn.readBoolean
  scala.io.StdIn.readDouble
  scala.io.StdIn.readFloat
  scala.io.StdIn.readLong
  scala.io.StdIn.readShort
With
readLinemethod you can pass string before input:val name = scala.io.StdIn.readLine("Your name: ")These methods assume, next input line as a single number, without leading or trailing whitespace, else NumberFormatException occurs